CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body starts from rest at time t=0, the acceleration time graph is shown in figure. The maximum velocity attained by the body will be:

322115.png

A
110m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
55m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
650m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
550m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 55m/s
We know that acceleration=ΔV/Δt so change in velocity ΔV=a×Δt, in other area under at graph is change in velocity so vu=area=12×10×11=55m/s
so final velocity v=u+55, putting initial velocity u=0 we get maximum velocity as 55m/s.

Its maximum because acceleration is positive for the given interval so velocity is increasing through out the interval.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon