a body starts from rest from the origin with an acceleration of 6m/s2 along the x axis and 8m/s2 along y axis its distance from the origin after 4 second is

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Solution

Dear Student,

Let,

$a_{x} : a c c e l e r a t i o n i n x - d i r e c t i o n = 6 m s^{- 2}_{a_{y} : a c c e l e r a t i o n i n y - d i r e c t i o n = 8 m s^{- 2}} P a r t i c l e s t a r t s f r o m r e s t, s o i n i t i a l v e l o c i t y i n x - d i r e c t i o n u_{x} a n d t h a t i n y - d i r e c t i o n, u_{y} a r e b o t h z e r o . T h e n b y k i n e m a t i c e q u a t i o n s : x = u_{x} t + \frac{1}{2} a_{x} t^{2}; a n d y = u_{y} t + \frac{1}{2} a_{y} t^{2} P l u g i n a b o v e v a l u e s i n t h e s e e q u a t i o n s w i t h t = 4 s e c . a n d g e t x = 48 m . y = 64 m . N o w, d i s \tan c e f r o m t h e o r i g i n i n 4 s e c i s g i v e n b y t h e r e s u l \tan t o f x a n d y i . e ., s = \sqrt{(x^{2} + y^{2})} t h i s g i v e s, s = 80 m .$
Regards,
Manoj Singh.

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