Question

A body starts from rest moving with a uniform acceleration reaches a velocity of 6m+s in 5 seconds and then moving with constant velocity for the next 4 seconds. Now the body decelerates uniformly and comes to rest in next 3 seconds. Draw the vt graph and hence calculate the acceleration, deceleration and distance travelled

Answer 1

Dear Student,


$$\begin{gathered} u=0,v=6m/s,t=5sec \\ a=\frac{6}{5}=1.2m/s^2 \\ cons\tan tvelocity6m/ssecfor4sec. \\ deaccn \\ a=\frac{-6}{3}=-2m/s^2 \\ dis\tan cetravels=\frac{1}{2}*1.2*5^2+6*4+6*3-\frac{2*3^2}{2}=48m \\ Regards \end{gathered}$$