A body starts moving with an initial velocity 50 m/s and acceleration 20 $m / s^{2}$ . How much distance it will cover in 4s ? Also, calculate its average speed during this time interval.

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Solution

Here,

u = 50 m/s, a = 20 $m / s^{2}$ ,

t = 4s, s = ?

s = ut + $\frac{{a t}^{2}}{2}$

= (50 × 4) + $\frac{20 x 4 x 4}{2}$

s = 200 + 160 = 360 m

Average speed = $\frac{T o t a l D i s t a n c e}{T i m e T a k e n}$

= $\frac{360}{4}$ m/s

Average speed = 90 m/s

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A body starts moving with an initial velocity 50 m/s and acceleration 20 m/s2. How much distance it will cover in 4s ? Also, calculate its average speed during this time interval.

Here, u = 50 m/s, a = 20 m/s2, t = 4s, s = ? s = ut + at22 = (50 × 4) + 20 x 4 x 42 s = 200 + 160 = 360 m Average speed = Total DistanceTime Taken = 3604 m/s Average speed = 90 m/s

A body starts moving with an initial velocity 50 m/s and acceleration 20 $m / s^{2}$ . How much distance it will cover in 4s ? Also, calculate its average speed during this time interval.

Here,

u = 50 m/s, a = 20 $m / s^{2}$ ,

t = 4s, s = ?

s = ut + $\frac{{a t}^{2}}{2}$

= (50 × 4) + $\frac{20 x 4 x 4}{2}$

s = 200 + 160 = 360 m

Average speed = $\frac{T o t a l D i s t a n c e}{T i m e T a k e n}$

= $\frac{360}{4}$ m/s

Average speed = 90 m/s