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Derivation of Velocity-Time Relation by Graphical Method

A body starts...

Question

A body starts with an initial velocity of 10 $m s^{- 1}$ and accelerates with 5 $m s^{- 2}$ . Find the distance covered by it in 5 sec.

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Solution

Given,
$u = 10 m / s$
$a = 5 m / s^{2}$
$t = 5 s e c$
From $2^{n d}$ equation of motion,
$S = u t + \frac{1}{2} a t^{2}$
$S = 10 \times 5 + \frac{1}{2} \times 5 \times 5 \times 5$
$S = 50 + 62.5$
$S = 112.5 m$

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