You visited us 1 times! Enjoying our articles? Unlock Full Access!

The Equations of Motion

A body starts...

Question

A body starts with an initial velocity of 10 $m s^{- 1}$ and acceleration 5 $m s^{- 2}$ .Find the distance covered by the body in 5 s.

Open in App

Solution

Initial velocity u = 10 m/s
Acceleration a = 5 m/s²
Time t = 5s
Let ‘S’ be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at²
S = (10)(5) + (1/2) (5) (5)²
S = 50 + 62.5
S = 112.5 m

Suggest Corrections

107

Similar questions

5 {ms}^{- 2}

100 m

{ms}^{- 1}

5 {m s}^{- 1}

1 {m s}^{- 2}

m s^{- 1}

m s^{- 2}

5 m s^{- 1}

25 m s^{- 1}

5 s

m s^{- 2} .

A body with an initial velocity of 5m/s has an acceleration of 2 $m / s^{2}$ . What is the distance covered by it in the fourth second?

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program