A body takes T minutes to cool from 62- C to61- C when the surrounding temperature is 30- C -The time taken by the body to cool from 46- C to 45-5- C is

A body takes $T$ minutes to cool from $62^{\circ} C$ to $61^{\circ} C$ when the surrounding temperature is $30^{\circ} C$ . The time taken by the body to cool form $46^{\circ} C$ to ${45.5}^{\circ} C$ is

Q. A body cools from

80^{\circ}

C to

50^{\circ}

C in

5

minutes. Calculate the time it takes to cool from

60^{\circ}

C to

30^{\circ}

C. The temperature of the surroundings is

20^{\circ}

Q. A hot body is allowed to cool. The surrounding temperature is constant at

30^{\circ} C

. The body takes time

t_{1}

to cool from

90^{\circ} C

89^{\circ} C

and time

t_{2}

to cool from

60^{\circ} C

{59.5}^{\circ} C

. Then,

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A body takes T minutes to cool from 62∘ C to61∘ C when the surrounding temperature is 30∘ C .The time taken by the body to cool from 46∘ C to 45.5∘ C is

The correct option is B Equal to T minutesIn first step 62−61T=K[62+612−30∘]⇒1T=K[31.5] ....(i) In second step, suppose process takes T min then 46−45.5T′=K[46+45.52−30]0.5T′=K[15.75] ...(ii) On diving equation (i) and (ii) 2T′T=2⇒T′=T

A body takes T minutes to cool from $62^{\circ}$ C to $61^{\circ}$ C when the surrounding temperature is $30^{\circ}$ C .The time taken by the body to cool from $46^{\circ}$ C to ${45.5}^{\circ}$ C is