Question

A body takes the following path and moves with constant speed. If $a_A$ and $a_B$ are the magnitude of its radial acceleration at A and B.

• A.
• B.
• C.
• D. none of these

Answer 1

The correct option is C

The radius of curvature is the radius of the osculating circle at that point of the curve.

We can clearly see that $R_A<R_B$
$\therefore \frac{v^2}{R_A}>\frac{v^2}{R_B}$ (as v is the speed and is constant)
$\Rightarrow a_A>a_B$