wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body thrown up along a frictionless inclined plane of angle of inclination 30 covers a distance of 40 m along the plane. If the body id projected with the same speed at an angle of 30 with the ground, it will have a range of
(Take g=10 ms2)


A

20 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

202 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

203 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

40 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

203 m


Let u be the initial speed with which the body is thrown along the inclined plane. As shown in the figure , the effective deceleration is given by
a=gsin θ=g sin 30=g2=5 ms2

Now, from the third equation of motion,
v2=u22as
0=u22×5×40
u=20 m/s
A projectile projected at angle θ=30 with this speed will have a range of
R=u2 sin 2 θg=20×20×sin 6010=203 m
Hence the correct choice is (c).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Projectile on an Incline
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon