A body thrown vertically up with a finite speed is caught back after $4 sec$ . The speed of the body with which it is thrown up is
(Take $g = 10 {m/s}^{2}$ )

10 m/sec

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20 m/sec

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30 m/sec

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40 m/sec

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Solution

The correct option is B $20 m/sec$
Given, time of flight of the body $= 4 sec$
We know that, time of flight is given as
$T = \frac{2 u}{g} \Rightarrow u = \frac{g T}{2} = \frac{10 \times 4}{2} = 20 m/s$

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A body thrown vertically up with a finite speed is caught back after 4 sec. The speed of the body with which it is thrown up is (Take g=10 m/s2)

The correct option is B 20 m/secGiven, time of flight of the body =4 sec We know that, time of flight is given as T=2ug⇒ u=gT2=10×42=20 m/s

A body thrown vertically up with a finite speed is caught back after $4 sec$ . The speed of the body with which it is thrown up is
(Take $g = 10 {m/s}^{2}$ )

The correct option is B $20 m/sec$
Given, time of flight of the body $= 4 sec$
We know that, time of flight is given as
$T = \frac{2 u}{g} \Rightarrow u = \frac{g T}{2} = \frac{10 \times 4}{2} = 20 m/s$