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Byju's Answer
Standard IX
Physics
Distance-Time Graphs
A body travel...
Question
A body travelling along a straight line traversed one third of the total distance with a velocity of 4 m/s.The remaining part of the distance was covered with a velocity 2 m/s for half the time and with velocity 6 m/s for the other half of time.The mean velocity averaged over the whole time of motion is
(a) 5 m/s
(b) 4 m/s
(c) 4.5 m/s
(d) 3.5 m/s
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Solution
Let
Total
distance
=
s
Time
taken
for
first
half
distance
:
Distance
,
s
1
=
s
2
t
1
=
s
/
2
4
=
s
8
Let
Time
taken
for
remaining
distance
=
t
2
+
t
3
Distance
travelled
with
2
m
/
s
,
s
2
=
2
t
2
Distance
travelled
with
6
m
/
s
,
s
3
=
6
t
3
Remaining
distance
:
s
2
=
s
2
+
s
3
s
2
=
2
t
2
+
6
t
3
But
,
t
2
=
t
3
Hence
,
s
2
=
2
t
2
+
6
t
2
s
2
=
8
t
2
t
2
=
s
16
t
3
=
t
2
=
s
16
Average
speed
for
the
whole
motion
:
v
=
s
1
+
s
2
+
s
3
t
1
+
t
2
+
t
3
=
s
s
8
+
s
16
+
s
16
=
s
s
8
+
s
8
=
s
s
4
=
4
m
/
s
Ans
:
Option
-
(
b
)
Suggest Corrections
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