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Question

A body travelling along a straight line traversed one third of the total distance with a velocity of 4 m/s.The remaining part of the distance was covered with a velocity 2 m/s for half the time and with velocity 6 m/s for the other half of time.The mean velocity averaged over the whole time of motion is
(a) 5 m/s
(b) 4 m/s
(c) 4.5 m/s
(d) 3.5 m/s

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Solution

Let Total distance=sTime taken for first half distance:Distance, s1=s2t1=s/24 =s8LetTime taken for remaining distance=t2+t3Distance travelled with 2 m/s, s2=2t2Distance travelled with 6 m/s,s3=6t3Remaining distance:s2=s2+s3s2=2t2+6t3But, t2=t3Hence,s2=2t2+6t2s2=8t2t2=s16t3=t2=s16Average speed for the whole motion:v=s1+s2+s3t1+t2+t3 =ss8+s16+s16 =ss8+s8 =ss4=4 m/sAns: Option - (b)

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