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Question

A body travels 200cm in the first two seconds and 220cmin the next 4 seconds. The velocity at the end Of the eleventh second is


A
0
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B
10cms1
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C
82cms1
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D
100cms1
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Solution

The correct option is B 10cms1

We are assuming that the body is under uniform acceleration here. Then, the total distance d travelled after the first t seconds is given by

d=ut+1/23
=u1Where u is the initial velocity and a is the acceleration$.$ We put the values of these quantities for the first 2 seconds$:$

200=2u+2a200=2u+2a

where u is in cm/s and a is in cm/s.

Then at the end of 6 seconds, the total distance travelled is 200+220= 420 cm. So,

420=6u+18a420=6u+18a

Upon solving, this gives u=115cm/s and a=15cm/s.

So velocity at the end of 7 seconds is given by:

v=u+atv=u+at$

=115105 = 10 cm/s

Hence,

option (B) is correct answer.


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