A body travels for 15sec starting from rest with constant acceleration. If it travels S1,S2 and S3 in the first 5 seconds, second 5 seconds and next five seconds respectively. The relation between S1,S2 and S3 is
A
S1=S2=S3
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B
5S1=3S2=S3
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C
S1=13S2=15S3
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D
S1=15S2=13S3
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Solution
The correct option is CS1=13S2=15S3 Since the body starts from rest. Therefore u=0.
By using second equation of motion
Distance covered in first 5 seconds will be S1=12a(5)2=25a2 ------(1)
Distance covered in first 10 seconds will be S1+S2=12a(10)2=100a2 ⇒S2=100a2−S1=75a2 ---------(2) Distance covered in first 15 seconds will be S1+S2+S3=12a(15)2=225a2 ⇒S3=225a2−S2−S1=125a2---------(3)
On comparing (1), (2) and (3) we will get S1=13S2 and S1=15S3