A body travels for $2 hours$ along a straight line at a uniform speed of $40 km/h$ , then takes a sharp left turn and travels a distance of $60 km$ with a uniform speed of $20 km/h$ . The average velocity of the body for whole journey is

20 km/h

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25 km/h

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30 km/h

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60 km/h

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Solution

The correct option is A $20 km/h$

$s_{1} = 40 \times 2 = 80 km$
$s_{2} = 60 km$
$t_{1} = 2 hr$
$t_{2} = \frac{60}{20} = 3 hr$
Displacement $= \sqrt{(80)^{2} + (60)^{2}} = 100 km$
$v_{avg} = \frac{100}{t_{1} + t_{2}} = 20 km/h$

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A body travels for 2 hours along a straight line at a uniform speed of 40 km/h, then takes a sharp left turn and travels a distance of 60 km with a uniform speed of 20 km/h. The average velocity of the body for whole journey is

The correct option is A 20 km/h s1=40×2=80 km s2=60 km t1=2 hr t2=6020=3 hr Displacement =√(80)2+(60)2=100 km vavg=100t1+t2=20 km/h

A body travels for $2 hours$ along a straight line at a uniform speed of $40 km/h$ , then takes a sharp left turn and travels a distance of $60 km$ with a uniform speed of $20 km/h$ . The average velocity of the body for whole journey is

The correct option is A $20 km/h$

$s_{1} = 40 \times 2 = 80 km$
$s_{2} = 60 km$
$t_{1} = 2 hr$
$t_{2} = \frac{60}{20} = 3 hr$
Displacement $= \sqrt{(80)^{2} + (60)^{2}} = 100 km$
$v_{avg} = \frac{100}{t_{1} + t_{2}} = 20 km/h$