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Question

# A body weighs 100 N on the surface of Earth. What will be the acceleration due to gravity acting on the body at a height of 3400 km above Earth's surface? Taking the mass of Earth=6×1024 kg, Radius of earth=6.4×106 m and G=6.7×10−11 Nm2kg−2.

A

6.18 ms2

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B

9.8 ms2

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C

6 ms2

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D

4.18 ms2

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Solution

## The correct option is B 9.8 ms−2 Given, mass of earth M=6×1024 kg, Radius of earth R=6.4×106 m, height h=3.4×106 m and G=6.7×10−11 Nm2kg−2. The value of g at a height h above the earth's surface is given by g=GM(R+h)2 =6.7×10−11×6×1024(6.4×106+3.4×106)2. On solving we get g=4.18 ms−2

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