A body weighs $200 N$ on the surface of the earth. How much will it weight halfway down to the centre of the earth ?

150 N

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200 N

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250 N

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100 N

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Solution

The correct option is D $100 N$
$g' = g (1 - \frac{d}{R}) \Rightarrow g' = g (1 - \frac{R / 2}{R}) \Rightarrow m g' = m g (\frac{1}{2}) ∴ W' = \frac{200}{2} = 100 N$

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Similar questions

Q. A body weighs

200 N

on the surface of the earth. How much will it weight halfway down to the centre of the earth ?

Q. A body weighs

200 N

on the surface of the earth. How much will it weight halfway down to the centre of the earth ?

Q. A body weighs

250 N

on the surface of the earth. How much will it weigh half way down to the centre of the earth.?

Q. A body weighs

250 N

on the surface of the earth. How much it weighs half way down to the centre of the earth ?

Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighed 250 N on the surface?

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A body weighs 200 N on the surface of the earth. How much will it weight halfway down to the centre of the earth ?

The correct option is D 100 Ng' = g (1−dR) ⇒g' = g (1−R/2R) ⇒mg' = mg(12) ∴ W' = 2002 = 100 N

A body weighs $200 N$ on the surface of the earth. How much will it weight halfway down to the centre of the earth ?

The correct option is D $100 N$
$g' = g (1 - \frac{d}{R}) \Rightarrow g' = g (1 - \frac{R / 2}{R}) \Rightarrow m g' = m g (\frac{1}{2}) ∴ W' = \frac{200}{2} = 100 N$