wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body weighs 20gf in air, 18.2gf in a liquid and 18.0gf in water. Calculate the relative density of the body and the liquid.

Open in App
Solution

Given,

Weight of the body in air = 20gf ( Wa)

Weight of the body in water = 18gf ( Ws)

Weight of the body in liquid =18.2gf ( Wl)

Now,

The loss of weight in the water = 20 - 18 or, 2 gf

So the relative density of the body is = Wa / ( wa - ws )

= 20 / 2

= 10

2) The weight loss in liquid = 20 - 18.2 or, 1.8 gf

So the relative density of the liquid is =( Wa - Wl ) / ( Wa - Ws )

= 1.8 / 2

= 0.9

Hope this helps :)

flag
Suggest Corrections
thumbs-up
23
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Density
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon