A body weighs $20 g f$ in air and $18.0 g f$ in water. The relative density of the material of body is X. Find (X-3).

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 7
Relative density of a substance is the ratio of its density to the density of a reference substance.
$r e l a t i v e d e n s i t y o f t h e b o d y = \frac{W e i g h t o f t h e b o d y i n a i r}{L o s s o f w e i g h t i n w a t e r}$ .
It is given that A body weighs $20 g f$ in air and $18.0 g f$ in water.
Therefore, $\frac{20}{20 - 18} = 10 = X$
Hence, the answer X-3 = 7.

Suggest Corrections

Similar questions

W

g f

W_{1}

g f

W_{1} = 8.00 + 0.05 N

W_{2} = 6.00 + 0.05 N

ρ_{r} = W_{1} / (W_{1} - W_{2})

(5.00 \pm 0.05)

(4.00 \pm 0.05)

A body of volume 100 $c m^{3}$ weighs 1 kgf in air.

Find : (i) its weight in water and (ii) its relative density.

A body weighs 40 gf in air, 36.4 gf in liquid and 36 gf in water. Calculate relative density of the body.

Join BYJU'S Learning Program