A body weighs $50 N$ in air and it weighs $40 N$ when immersed in water. Find out the force of buoyancy acting on the body in water.

90 N

, upward direction

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10 N

, downward direction

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10 N

, upward direction

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90 N

, downward direction

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Solution

The correct option is C $10 N$ , upward direction
Given:
Weight of body in air ( $w_{1}$ ) $= 50 N$
Weight of body when immersed in water ( $w_{2}$ ) $= 40 N$

We know that, buoyant force ( $F_{B}$ ) always acts on the body in the upward direction, and the value of buoyant force is equal to loss in weight of the immersed body in water ( $w$ ).
$∴ w = F_{B} = w_{1} - w_{2}$
$\Rightarrow F_{B} = 50 - 40$
$\Rightarrow F_{B} = 10 N$

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