A body weighs 60 kg on the surface of earth how much would it weigh on the surface of a Planet whose mass is 1/9 the mass of the earth and radius is half that of Earth

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Solution

$D e a r s t u d e n t, a c c e l e r a t i o n d u e t o g r a v i t y = \frac{G M_{P l a n e t}}{(R a d i u s o f p l a n e t)^{2}} o n E a r t h, g = \frac{G M_{E}}{{R_{E}}^{2}} f o r o t h e r p l a n e t, g' = \frac{G M_{P}}{{R_{P}}^{2}} g i v e n M_{P} = \frac{M_{E}}{9} R_{P} = \frac{R_{E}}{2} s o g' = \frac{G M_{E} \times 4}{9 \times (R_{E})^{2}} g' = \frac{4}{9} g w e i g h t o n p l a n e t = \frac{4}{9} \times 60 = 26.66 k g R e g a r d s$

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A body weighs 60 kg on the surface of earth how much would it weigh on the surface of a Planet whose mass is 1/9 the mass of the earth and radius is half that of Earth

Dear student,acceleration due to gravity=GMPlanet(Radius of planet)2on Earth,g=GMERE2for other planet,g'=GMPRP2given MP=ME9RP=RE2so g'=GME×49×(RE)2g'=49gweight on planet=49×60=26.66kgRegards