A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of earth?
g′=g(1+hR)2
Here h=R2
g′=g(1+12)2 =49g=4.44 m/s2
Now the force experienced by the object at half the radius of earth is
F′=mg′=7.2×4.44≈32 N