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Question

A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of earth?

A
30 N
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B
24 N
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C
48 N
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D
32 N
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Solution

The correct option is D 32 N
Mass m=7210=7.2 kg
Now at some height h, acceleration due to gravity is given by

g=g(1+hR)2
Here h=R2
g=g(1+12)2 =49g=4.44 m/s2

Now the force experienced by the object at half the radius of earth is
F=mg=7.2×4.4432 N


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