A body weight $50 N$ in air and when immersed in water weight only $25 N$ . Find the relative density:

2.5

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5

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5.2

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2

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Solution

The correct option is A $2$
$F_{1} = 50 N$ $F_{2} = 25 N$
$\frac{F_{1}}{F_{2}} = \frac{50}{25}$ or relative masses
$\frac{M_{1}}{M_{2}} = \frac{50}{25} = 2$
density $= \frac{M}{N}$ and volume ( $V$ ) remain constant
Relative density $= \frac{d_{1}}{d_{2}} = \frac{50}{25} = 2$

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A body weight 50N in air and when immersed in water weight only 25N. Find the relative density:

The correct option is A 2F1=50N F2=25NF1F2=5025 or relative massesM1M2=5025=2density =MN and volume (V) remain constantRelative density =d1d2=5025=2

A body weight $50 N$ in air and when immersed in water weight only $25 N$ . Find the relative density:

The correct option is A $2$
$F_{1} = 50 N$ $F_{2} = 25 N$
$\frac{F_{1}}{F_{2}} = \frac{50}{25}$ or relative masses
$\frac{M_{1}}{M_{2}} = \frac{50}{25} = 2$
density $= \frac{M}{N}$ and volume ( $V$ ) remain constant
Relative density $= \frac{d_{1}}{d_{2}} = \frac{50}{25} = 2$