A body weight 72 N on the surface of the earth. What is the gravitational force acting on it due to the earth at a height equal to half the radius of the earth from the surface?
Given that,
Weight W=72N
Height =h
Now, the acceleration due to gravity at a height h from the surface of the earth
gh=g(RR+h)2
gh=g⎛⎜ ⎜ ⎜⎝RR+R2⎞⎟ ⎟ ⎟⎠2
gh=g(2R3R)2
gh=49g
Now, the gravitational force on the body at a height h is
F=mgh
F=72×49
F=32N
Hence, the gravitational force is 32 N