A body when acted upon by a force of 10kgf gets displaced by 0.5m calculate the work done by the force when the displacement is in the direction of force

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Solution

F=10kgf
=109.8 N. (1kgf=9.8N)
=98N
since displacement is in same direction as force applied,then
Work done=force displacementcos0
=98.5=49joules

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A body when acted upon by a force of 10kgf gets displaced by 0.5m calculate the work done by the force when the displacement is in the direction of force

F=10kgf =10*9.8 N. (1kgf=9.8N) =98N ​​​​​​since displacement is in same direction as force applied,then Work done=force * displacement*cos0 =98*.5=49joules

F=10kgf
=109.8 N. (1kgf=9.8N)
=98N
since displacement is in same direction as force applied,then
Work done=force displacementcos0
=98.5=49joules