Question

A body which is intially at rest covers a distance of 6 m in 4 seconds. Calculate:
(a) The acceleration
(b) The final velocity [3 MARKS]

Answer 1

Acceleration : 1.5 Marks
Final Velocity : 1.5 Marks

(a) Here ,
$u=0,s=6m,t=4s$
Using,
$s=ut+\frac{{at}^2}{2}$
$6=(0\times 4)+\frac{a\times 4\times 4}{2}$
solving we get,
$a=0.75m/s^2$

(b) $v=u+at$
$v=0+(0.75\times 4)$
$v=3m/s$