A body whose volume is $100 c m^{3}$ weighs $10 N$ in air, Find it weight in water.
(Take $g = 10 m s^{- 2}$ , density of water $= 1000 k g m^{- 3}$ )

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Solution

Given that,

Weight in air $10 N$

Volume of body $V = 100 c m^{3}$

Density of water $ρ = 1000 k g / m^{3}$

We know that,

Weight in water = weight in air – buoyancy force

$W_{w} = 10 - 10^{- 4} \times 1000 \times 10$

$W_{w} = 10 - 1$

$W_{w} = 9 N$

Hence, the weight of body in water is $9 N$

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A body of volume 100 $c m^{3}$ weighs 1 kgf in air.

Find : (i) its weight in water and (ii) its relative density.

100 c m^{3}

5 k g f

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4000 k g m^{- 3}

1000 k g m^{- 3}

(g = 10 m s^{- 2})

100 c m^{3}

1 k g f

100 c m^{3}

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