A body with an initial velocity of $18 k m h^{- 1}$ accelerates uniformly at the rate of $9 c m s^{- 2}$ over a distance of $200 m$ . Calculate the acceleration in $m s^{- 2}$

0.09 k m s^{- 2}

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0.09 m s^{- 2}

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9 m s^{- 2}

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9 k m s^{- 2}

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Solution

The correct option is B $0.09 m s^{- 2}$
Acceleration $= 9 c m s^{- 2} = \frac{9}{100} m s^{- 2}$
$= 0.09 m s^{- 2}$

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