A body with an initial velocity of $18 k m p h$ accelerates uniformly at $9 c m s^{- 2}$ over a distance of $200 m$ . Find its final velocity in $m s^{- 1}$ .

\sqrt{61}

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\sqrt{78}

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\sqrt{51}

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None of these

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Solution

The correct option is A $\sqrt{61}$
$a = 9 c m s^{- 2} = 0.09 m s^{- 2}$
$u = 18 k m p h = \frac{18 \times 1000}{60 \times 60} m s^{- 1} = 5 m s^{- 1}$
$s = 200 m$
$v^{2} = u^{2} + 2 a s = (5)^{2} + (2 \times 0.09 \times 200) = 61$
or $v = \sqrt{61} m s^{- 1}$

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A body with an initial velocity of 18 kmph accelerates uniformly at 9 cms−2 over a distance of 200 m. Find its final velocity in ms−1.

The correct option is A √61a=9cms−2=0.09ms−2u=18kmph=18×100060×60ms−1=5ms−1s=200mv2=u2+2as=(5)2+(2×0.09×200)=61or v=√61ms−1

A body with an initial velocity of $18 k m p h$ accelerates uniformly at $9 c m s^{- 2}$ over a distance of $200 m$ . Find its final velocity in $m s^{- 1}$ .

The correct option is A $\sqrt{61}$
$a = 9 c m s^{- 2} = 0.09 m s^{- 2}$
$u = 18 k m p h = \frac{18 \times 1000}{60 \times 60} m s^{- 1} = 5 m s^{- 1}$
$s = 200 m$
$v^{2} = u^{2} + 2 a s = (5)^{2} + (2 \times 0.09 \times 200) = 61$
or $v = \sqrt{61} m s^{- 1}$