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Question
A body with mass 1 kg moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest x=2m, than its speed when it crosses x=5m is (Neglect dissipative forces)
A body with mass 1 kg moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest x=2m, than its speed when it crosses x=5m is (Neglect dissipative forces)
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Solution
The correct option is A zero
F=−dU/dxThus F = 4 {x=1 to x=3.5}, -2{x=3.5 to x=4.5}KEi=0,KEf=WF=∫3.524dx−∫4.53.52dx=4J0.5(1)v2=4=>v=√8=2√2m/s
F=−dU/dx
Thus F = 4 {x=1 to x=3.5}, -2{x=3.5 to x=4.5}
KEi=0,KEf=WF=∫3.524dx−∫4.53.52dx=4J
0.5(1)v2=4=>v=√8=2√2m/s
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