A bodyweight $5 N$ in the air and $2 N$ when immersed in a liquid. The buoyant force is:

2 N

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3 N

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4 N

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5 N

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Solution

The correct option is C $3 N$
Given, The weight of the body in the air is $= 5 N,$
When immersed in water, the weight of the body $= 2 N$
In water, there will be a buoyancy force Which opposes the weight of the body.
Therefore the buoyant force is equal to $= 5 N - 2 N = 3 N$

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