Question

A bolt of grade 4.6 is used to join two plates. The sum of ultimate tensile strength and yield strength of bolt will be ____ $N/m{m}^2$

Answer 1

Grade of bolt = 4.6
So ultimate tensile strength
$f_u=400N/m{m}^2$
Grade 4.6 $\Rightarrow$
60% of $f_u$ will be yield strength so
$f_y=0.6\times 400=240N/m{m}^2$
$f_u+f_y=400+240=640N/m{m}^2$