A bomb is dropped from an aeroplane when it is directly above a target at a height of 1000 m.The aeroplane is moving horizontally with a speed of $500 k m h^{- 1}$ . By the how much distance will the bomb miss the target?

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Solution

Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall

Horizontal distance $(d) =$ Time of fall $\times$ Horizontal speed
$\Rightarrow d = t \times v$
$\Rightarrow d = \sqrt{\frac{2 h}{g}} \times 500 k m / h$
$\Rightarrow d = \sqrt{\frac{2 \times 1000}{10}} \times 500 \times \frac{5}{18} m / s$
$\Rightarrow d = 1964.2 m$

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A bomb is dropped from an aeroplane when it is directly above a target at a height of 1000 m.The aeroplane is moving horizontally with a speed of 500kmh−1. By the how much distance will the bomb miss the target?

A bomb is dropped from an aeroplane when it is directly above a target at a height of 1000 m.The aeroplane is moving horizontally with a speed of $500 k m h^{- 1}$ . By the how much distance will the bomb miss the target?