A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8kg mass is 6 m/sec. The kinetic energy of the other mass is

48 J

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32 J

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24 J

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288 J

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Solution

The correct option is D
288 J

As the initial momentum of bomb was zero, therefore after explosion two

parts should possess numerically equal momentum

$i . e . m_{A} v_{A} = m_{B} v_{B} \Rightarrow 8 \times 6 \Rightarrow v_{A} = 12 m / s$

$∴ K i n e t i c e n e r g y o f o t h e r m a s s A, = \frac{1}{2} m_{A} v_{A}^{2}$

K = $\frac{1}{2}$ $4 \times 144$ = 288 J

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A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8kg mass is 6 m/sec. The kinetic energy of the other mass is

The correct option is D 288 J As the initial momentum of bomb was zero, therefore after explosion two parts should possess numerically equal momentum i.e.mAvA=mBvB⇒8×6⇒vA=12m/s ∴Kinetic energy of other mass A,=12mAv2A K = 12 4×144 = 288 J