A bomb of $12 K g$ explodes into two pieces of masses $4 K G$ and $8 K g$ . The velocity of $8 K g$ mass is $6 m / s e c$ The kinetic energy of the other mass is

48 J

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32 J

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24 J

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288 J

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Solution

The correct option is D $288 J$
$M - 1 V_{1} = M_{2} V_{2}$
$= 2 (5) (6) = (4) V_{2}$
$= 12 = V_{2}$
Kinetic Energy $= \frac{1}{2} m V^{2}$
$= 1 / 2 \times 4 \times 12 \times 12$
$= 288 J$

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A bomb of 12Kg explodes into two pieces of masses 4KG and 8Kg. The velocity of 8Kg mass is 6m/sec The kinetic energy of the other mass is

The correct option is D 288JM−1V1=M2V2=2(5)(6)=(4)V2=12=V2Kinetic Energy =12mV2=1/2×4×12×12=288J

A bomb of $12 K g$ explodes into two pieces of masses $4 K G$ and $8 K g$ . The velocity of $8 K g$ mass is $6 m / s e c$ The kinetic energy of the other mass is

The correct option is D $288 J$
$M - 1 V_{1} = M_{2} V_{2}$
$= 2 (5) (6) = (4) V_{2}$
$= 12 = V_{2}$
Kinetic Energy $= \frac{1}{2} m V^{2}$
$= 1 / 2 \times 4 \times 12 \times 12$
$= 288 J$