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Question

A bomb of mass 16kg at rest explodes into two pieces of masses 4kg and 12kg. The velocity of the 12kg mass is 4ms1. The kinetic energy of the other mass is

A
144J
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B
288J
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C
192J
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D
96J
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Solution

The correct option is B 288J
Here, momentum of the system is remaining conserved as no external force is acting on the bomb (system).

Initial momentum (before explosion )
= Final momentum (after explosion)
Let velocity of 4kg mass be vms1. From momentum conservation, we can say that its direction is opposite to velocity of 12kg mass.
From pi=pf0=12×44×v
or v=12m/s
KE of 4kg mass=4×(12)22=288J

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