A bomb of mass 16kg at rest explodes into two pieces of masses 4kg and 12kg. The velocity of the 12kg mass is 4ms−1. The kinetic energy of the other mass is
A
144J
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B
288J
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C
192J
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D
96J
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Solution
The correct option is B288J Here, momentum of the system is remaining conserved as no external force is acting on the bomb (system).
Initial momentum (before explosion )
= Final momentum (after explosion)
Let velocity of 4kg mass be vms−1. From momentum conservation, we can say that its direction is opposite to velocity of 12kg mass.
From pi=pf⇒0=12×4−4×v
or v=12m/s ∴KE of4kg mass=4×(12)22=288J