A bomb of mass 16kg at rest explodes into two pieces of masses 4kg and 12kg . The velocity of the 12kg mass is 4ms−1. The kinetic energy of the other mass is
A
144J
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B
288J
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C
192J
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D
96J
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Solution
The correct option is B288J Let the velocity and mass of 4kg piece by v1 and
velocity and mass of 12kg piece be v2 and m2
Applying conservation of linear momentum m2v1=m1v2 ⇒v1=12×44=12 ms−1
Kinetic energy is ∴KE1=12m1v21=12×4×144=288J
The correct option is (B)