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Question

a bomb of mass 3 kg at rest explodes into two parts one part of mass 2 kg is found at a speed of 12 metre per second towards the east what is the velocity of the other part

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Solution


Dear Student,
Using conservation of momentum. MV = m1v1 + m2v2Here M = 3kg, V =0, m1 = 2kg, v1=12m/s, m2 = 3-2 =1kg, v2=?So,3(0) = 2(12) + 1(v2)0 -24 m/s =v2v2 = -24m/s(-) sign indicates that the direction of second particle isopposite to the first particle that is second particle moved due west.
Regards.

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