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Question

A bomb of mass 3m is kept inside a closed box of mass 3m and length 4L at it's center. It explodes in two parts of mass m and 2m. The two parts move in opposite directions and stick to the opposite sides of the walls of box. The box is kept on a smooth horizontal surface. What is the distance moved by the box during this time interval ?
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Solution

ΔXcm=M1ΔX1+M2ΔX2+M3ΔX3M1+M2+M3

0=3MX+2M(M+2L)+(X2L)

6MX=2ML4ML

X=L3


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