A bomb of mass 3m kg explodes into two pieces of mass m kg and 2m kg . If the velocity of m kg mass is 16 m/s, the total energy released in the explosion is
A
192mJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
96mJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
384mJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
768mJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A192mJ Given that,
Initial velocity of mass 3m kg,(vi)=0 m/s
after explosion
By the conservation of momentum,
initial momentum of the systme = final momentum of the system
initial momentum of the system = 0 0=mAvA−mBvB ⇒mAvA=mBvB ⇒m×16=2m×vB ⇒vB=8m/s
Energy release during explosion is kinetic energy of system
=12mAv2A+12mBv2B=192mJ ∴(a).