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Question

A bomb of mass 3m kg explodes into two pieces of mass m kg and 2m kg . If the velocity of m kg mass is 16 m/s, the total energy released in the explosion is

A
192m J
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B
96m J
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C
384m J
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D
768m J
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Solution

The correct option is A 192m J
Given that,
Initial velocity of mass 3m kg,(vi)=0 m/s
after explosion


By the conservation of momentum,
initial momentum of the systme = final momentum of the system
initial momentum of the system = 0
0=mAvAmBvB
mAvA=mBvB
m×16=2m×vB
vB=8 m/s
Energy release during explosion is kinetic energy of system
=12mAv2A+12mBv2B=192m J
(a).

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