A bomb of mass 9 kg explodes into two pieces of masses 3 kg and 6 kg. the velocity of mass 3 kg is 15 metre per second. calculate the kinetic energy of mass 6 kg.

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Solution

Conserving law of linear momentum:

Let v be the velocity of 6 kg mass after the explosion.

therefore 3(15) = 6(v) or v = 7.5 m/s

kinetic energy of the 6 kg mass = 0.5(6)(v)²=168.75 Joules

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A bomb of mass 10Kg explodes into two pieces of masses 4Kg and 6Kg . If kinetic energy of 4Kg piece is 200J. Find out kinetic energy of 6Kg piece

A.)400/3J B.)200/3J. C.)100/3J. D.)300/5J

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