Question

A book containing 100 pages is opened at random. Find the probability that a doublet page is found.

• A. $\frac{9}{100}$
• B. $\frac{9}{10}$
• C. $\frac{1}{10}$
• D. $\frac{1}{5}$

Answer 1

Answer: (A)

$\frac{9}{100}$

no. of doubles from $1$ to $100:11,22,33,44,55,66,77,88,99$.

$\therefore$ probability $=\frac{\text{no. of favorable outcomes}}{\text{total no. of outcomes}}$

$=\frac{9}{10}$

$\therefore$ Probability $=\frac{9}{100}$