A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final days were respectively $1094, 1812, 2050 a n d 2751$ . Find the total number of tickets sold on all the four days.

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Solution

Given,
The number of tickets sold at the counter on the first day $= 1094$
The number of tickets sold at the counter on the second day $= 1812$
The number of tickets sold at the counter on the third day $= 2050$
The number of tickets sold at the counter on the final day $= 2751$
The total number of tickets sold on all the four days $= 1094 + 1812 + 2050 + 2751 = 7, 707$ .
Hence, the total number of tickets sold on all the four days is $7, 707$ .

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A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final days were respectively 1094,1812,2050and2751. Find the total number of tickets sold on all the four days.

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final days were respectively $1094, 1812, 2050 a n d 2751$ . Find the total number of tickets sold on all the four days.