A book exhibition was held for four days in a school.The number of tickets sold at the counter on the first, second,third and final day was respectively $1094, 1812, 2050$ and $2751$ .Find the total number of tickets sold on all the four days.

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Solution

Total tickets sold $=$ Tickets sold on first day $+$ Tickets sold on secnd day

$+$ Tickets sold on third day $+$ Tickets sold on fourth day

$= 1094 + 1812 + 2050 + 2751$

$= 7707$

So, total tickets sold $= 7, 707$

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A book exhibition was held for four days in a school.The number of tickets sold at the counter on the first, second,third and final day was respectively 1094,1812,2050 and 2751.Find the total number of tickets sold on all the four days.

Total tickets sold=Tickets sold on first day+Tickets sold on secnd day+Tickets sold on third day+Tickets sold on fourth day=1094+1812+2050+2751=7707So, total tickets sold=7,707

A book exhibition was held for four days in a school.The number of tickets sold at the counter on the first, second,third and final day was respectively $1094, 1812, 2050$ and $2751$ .Find the total number of tickets sold on all the four days.

Total tickets sold $=$ Tickets sold on first day $+$ Tickets sold on secnd day

$+$ Tickets sold on third day $+$ Tickets sold on fourth day

$= 1094 + 1812 + 2050 + 2751$

$= 7707$

So, total tickets sold $= 7, 707$