Question

A book has pages numbered from 1 to 100. If a page is chosen at random, what is the probability that the number of the page is divisible by 9?

• A.

  $\frac{6}{85}$

• B.

  $\frac{1}{10}$

• C.

  $\frac{11}{100}$

• D.

  $\frac{6}{10}$

Answer 1

The correct option is C

$\frac{11}{100}$

Given,

Total number of pages in the book = 100

The required page numbers such that it is divisible by 9= 09, 18, 27, 36, 45, 54, 63, 72, 81, 90,99

That makes 11 favourable outcomes out of 100.

$\text{Thus, the required probability}=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

= $\frac{11}{100}$