Question

A book has pages numbered from 1 to 90. If a page is chosen at random, what is the probability that the number of the page is divisible by 8?

• A. $\frac{11}{90}$
• B. $\frac{1}{9}$
• C. $\frac{1}{10}$
• D. $\frac{2}{15}$

Answer 1

The correct option is A

$\frac{11}{90}$

Given,

Total number of pages in the book = 90

The page numbers that are divisible by 8 = 08, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88.

= 11

That makes 11 favourable outcomes out of 90.

$\text{Thus, the required probability}=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

= $\frac{11}{90}$