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Question

A book of mass 5 kg is placed on a table and it is pressed by 10 N force then, normal force exerted by the table on the book is?


Solution

Mass of book=5kg
Then force exerted by earth on book= mg=5×9.8=49 N
External force exerted on book = 10 
By Newton's third law of motion we get,
Force exerted by table on book= mg+10=49+10=59N

Hence force exerted by table on book = 59 N

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