Question

A boost converter feeds an average current of 10 A to a load. The value of duty cycle and chopping frequency are 0.40 and 50 kHz respectively. Filter inductance and capacitance are of 10 mH and 120 $\mu$F respectively. The peak-to-peak ripple voltage will be

• A. 0.75 V
• B. 0.66 V
• C. 0.33 V
• D. 1.82 V

Answer 1

The correct option is B 0.66 V

For boost converter, peak-to-peak ripple voltage,
$\Delta V_0=\frac{\alpha I_0}{fC}=\frac{0.40\times 10}{50\times {10}^3\times 120\times {10}^{-6}}=0.66V$