Question

A borrows $RS.8000$ at $12\%$ per annum simple interest and $B$ borrows $Rs.9100$ at $10\%$ per annum simple ineterst. In how many years will their amounts be equal?

Answer 1

SI

A

Amount - 8000

Rate 12%

Let year x

$\Rightarrow$ Amount = $S{I}_A+P_A$

$\Rightarrow \frac{8000\times 12\times x}{100}$

B

Amount 9100

Rate 10%

let year x

$Amoun{t}_B=S{I}_B+P_B$

$\frac{9100\times 10\times x}{100}$

$\Rightarrow 960x+8000=910x+9100$

$960x-910x=9100-8000$

$50x=1100$

$x=22$

After 22 yeras, Amount will be equal