A bottle can hold $100 g$ of water at $40^{o} C$ . What mass of sea water (Density $= 1030 k g / m^{2}$ ) can it hold?

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Solution

We know that the density of a body is defined as:
$d e n s i t y = \frac{m a s s}{v o l u m e}$

Substitute the values in above expression:
$1000 = \frac{100}{v}$

$v = 0.1$

mass of seawater $= d e n s i t y \times v o l u m e$
$= 1030 \times 0.1 = 103 g$

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A bottle can hold 100g of water at 40oC. What mass of sea water (Density =1030kg/m2) can it hold?

We know that the density of a body is defined as:density=massvolumeSubstitute the values in above expression:1000=100vv=0.1mass of seawater = density×volume =1030×0.1=103 g

A bottle can hold $100 g$ of water at $40^{o} C$ . What mass of sea water (Density $= 1030 k g / m^{2}$ ) can it hold?

We know that the density of a body is defined as:
$d e n s i t y = \frac{m a s s}{v o l u m e}$

Substitute the values in above expression:
$1000 = \frac{100}{v}$

$v = 0.1$

mass of seawater $= d e n s i t y \times v o l u m e$
$= 1030 \times 0.1 = 103 g$